![]() You can thus say that the unknown particle will have a mass number equal to #4# and an atomic number equal to #2#. #color(white)(a)74 = color(white)(a)72 + Z -># conservation of charge In any nuclear reaction, charge and mass must be conserved. ![]() Here #A# represents the mass number of the particle, which as you know tells you the number of protons and electrons present in the nucleus, and #Z# represents the atomic number, which is simply the number of protons present in the nucleus. Your goal here is to find the values of #A# and #Z#, which in turn will give you the identity of the particle emitted from the nucleus of the tungsten-159 isotope. The nuclear equation given to you describes the decay of tungsten-159 to hafnium-155
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